-2^2-v+12=-3v^2+6v

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Solution for -2^2-v+12=-3v^2+6v equation: 



-2^2-v+12=-3v^2+6v

We move all terms to the left:

-2^2-v+12-(-3v^2+6v)=0

We add all the numbers together, and all the variables

-(-3v^2+6v)-1v+8=0

We get rid of parentheses

3v^2-6v-1v+8=0

We add all the numbers together, and all the variables

3v^2-7v+8=0

a = 3; b = -7; c = +8;
Δ = b2-4ac
Δ = -72-4·3·8
Δ = -47
Delta is less than zero, so there is no solution for the equation

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